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4.905x^2+16x-6=0
a = 4.905; b = 16; c = -6;
Δ = b2-4ac
Δ = 162-4·4.905·(-6)
Δ = 373.72
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-\sqrt{373.72}}{2*4.905}=\frac{-16-\sqrt{373.72}}{9.81} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+\sqrt{373.72}}{2*4.905}=\frac{-16+\sqrt{373.72}}{9.81} $
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